#!/usr/bin/env python3


from typing import TextIO


def nice_or_naughty(string: str) -> int:
    """0 for naughty and 1 for nice"""
    # count vowels
    cv = (
        string.count("a")
        + string.count("e")
        + string.count("i")
        + string.count("o")
        + string.count("u")
    )

    if cv < 3:
        return 0

    # twice in a row
    dbl = 0
    for ch in range(0, len(string)):
        if len(string) > ch + 1 and string[ch] == string[ch + 1]:
            dbl += 1

    if dbl == 0:
        return 0

    # naughty strings
    n = ("ab", "cd", "pq", "xy")
    for x in n:
        if x in string:
            return 0

    return 1


def nn2(string: str) -> int:
    # first
    a = 0  # we can only have 0 or 1, because of the return
    # not anymore b/c it's BOTH, but whatever

    for c in range(0, len(string) - 1):
        pair = string[c : c + 2]
        # print("pair is", pair)

        for d in range(c + 2, len(string) - 1):  # , len(string) - 2):
            # print("trying to match", pair, string[d : d + 2])
            if d + 1 < len(string) and string[d : d + 2] == pair:
                # print("yay")
                a += 1
                break
        else:  # ?? huuhhh? https://stackoverflow.com/questions/653509/breaking-out-of-nested-loops
            continue

        break

    # second
    b = 0

    for c in range(0, len(string) - 2):
        if string[c] == string[c + 2]:
            b += 1
            break

    if a == 1 and b == 1:
        return 1
    return 0


def part1(file: TextIO) -> int:
    count = 0

    for string in file:
        count += nice_or_naughty(string.strip())

    return count


def part2(file: TextIO) -> int:
    count = 0

    for string in file:
        count += nn2(string.strip())

    return count


if __name__ == "__main__":
    with open("day05.txt", "r") as f:
        print(part1(f))

    with open("day05.txt", "r") as f:
        print(part2(f))